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Dividing One Polynomial by Another Division of polynomials is conceptually the same as the binary division we discussed for an encoder We divide the first term of the dividend by the first term of the divisor to get the first term of the quotient We multiply the term in the quotient by the divisor and subtract the result from the dividend We repeat the process until the dividend degree is less than the divisor degree We will show an example of division later in this chapter Shifting A binary pattern is often shifted a number of bits to the right or left Shifting to the left means adding extra Os as rightmost bits; shifting to the right means deleting some rightmost bits Shifting to the left is accomplished by multiplying each term of the polynomial where m is the number of shifted bits; shifting to the right is accomplished by by dividing each term of the polynomial by xn The following shows shifting to the left and to the right Note that we do not have negative powers in the polynomial representation

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CompTIA fixes the price, no matter what testing center you use The cost of the exam depends on whether you work for a CompTIA member At press time, the cost for nonCompTIA members is $239 (US) If your employer has a CompTIA membership, you can save money by obtaining an exam voucher In fact, even if you don t work for a CompTIA member, you can purchase a voucher from member companies and take advantage of significant member savings You simply buy the voucher and then use the voucher to pay for the exam Most vouchers are delivered to you on paper, but the most important element is the unique voucher number that you ll generally receive via e-mail from the company that sells the voucher to you That number is your exam payment, so protect it from prying eyes until you re ready to schedule your exam CompTIA requires any company that resells vouchers to bundle them with some other product or service Because this requirement is somewhat vague, voucher resellers have been known to throw in some pretty lame stuff, just to meet the requirement and keep their overhead low My company, Total Seminars, is an authorized CompTIA member and voucher reseller, and we bundle our CompTIA Network+ vouchers with something you can actually use: our excellent test simulation software It s just like the CD-ROM in the back of this book, but with hundreds more questions to help you prepare for the CompTIA Network+ exam If you re in the United States or Canada, you can visit wwwtotalsemcom or call 800446-6004 to purchase vouchers As I always say, You don t have to buy your voucher from us, but for goodness sake, get one from somebody! Why pay full price when you have a discount alternative You must pay for the exam when you schedule, either online or by phone If you re scheduling by phone, be prepared to hold for a while Have ready your social security number (or the international equivalent) and either a credit card or a voucher number when you call or begin the online scheduling process If you require any special accommodations, both Prometric and Pearson VUE will be able to assist you, although your selection of testing locations may be a bit more limited International prices vary; see the CompTIA Web site for international pricing Of course, prices are subject to change without notice, so always check the CompTIA Web site for current pricing!.

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Shifting left 3 bits: Shifting right 3 bits:

When we augmented the dataword in the encoder of Figure 1015, we actually shifted the bits to the left Also note that when we concatenate two bit patterns, we shift the first polynomial to the left and then add the second polynomial Cyclic Code Encoder Using Polynomials Now that we have discussed operations on polynomials, we show the creation of a codeword from a dataword Figure 1022 is the polynomial version of Figure 1015 We can see that the process is shorter The dataword 1001 is represented as x 3 + 1 The divisor 1011 is represented as x 3 + x + 1 To find the augmented dataword, we have left-shifted the dataword 3 bits (multiplying by x\ The result is x6 + x3 Division is straightforward We divide the first term of the dividend, x 6, by the first term of the divisor, x 3 The first term of the quotient is then x 6/x 3 , or x 3 Then we multiply x 3 by the divisor and subtract (according to our previous definition of subtraction) the result from the dividend The

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result is x 4 , with a degree greater than the divisor's degree; we continue to divide until the degree of the remainder is less than the degree of the divisor Figure 1022 CRC division using polynomials

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