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USE InsideTSQL2008; SELECT E1.firstname, E1.lastname AS emp1, E2.firstname, E2.lastname AS emp2 FROM HR.Employees AS E1 CROSS JOIN HR.Employees AS E2;

This scenario was fairly simple, but in cases where you mix different types of joinsnot to mention new table operators that were added in SQL Server 2005 (for example, APPLY, PIVOT, UNPIVOT)it might not be that simple. Furthermore, using left outer joins all along the way is very artificial. It's more intuitive to think of the query as a single left outer join, where the left table is the Customers table and the right table is the result of inner joins between all the other tables. Both ANSI SQL and T-SQL allow you to control the logical order of join processing: SELECT DISTINCT C.CompanyName AS customer, S.CompanyName AS supplier FROM dbo.Customers AS C LEFT OUTER JOIN (dbo.Orders AS O JOIN dbo.[Order Details] AS OD ON OD.OrderID = O.OrderID JOIN dbo.Products AS P ON P.ProductID = OD.ProductID JOIN dbo.Suppliers AS S ON S.SupplierID = P.SupplierID) ON O.CustomerID = C.CustomerID;

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Because the Employees table contains nine rows, the result set contains 81 rows. Here s the ANSI SQL-89 syntax you would use for the same task:

In object-oriented programming (OOP), the most important concept is a class used as a template for instantiating (creating) objects; objects are variables that physically live in computer memory . So what are the most important concepts in the relational world Note My views on this subject have been largely affected by the work of Chris J . Date and Hugh

SELECT E1.firstname, E1.lastname AS emp1, E2.firstname, E2.lastname AS emp2 FROM HR.Employees AS E1, HR.Employees AS E2;

Darwen in their famous book Foundation for Object/Relational Databases: The Third Manifesto (Addison-Wesley Professional, 1998) .

Technically, the parentheses are ignored here, but I recommend you use them because they will help you write the query correctly. Using parentheses caused you to change another aspect of the query, which is the one that the language really uses to determine the logical order of processing. If you

The optimizer produces the same plan for both the ANSI SQL-92 and the ANSI SQL-89 syntaxes, so you shouldn t have any concerns about performance. For reasons that I will explain later in the chapter, I recommend that you stick to the ANSI SQL-92 syntax. Now let s look at more sophisticated uses of cross joins. In 6, Subqueries, Table Expressions, and Ranking Functions, I presented a fundamental technique to generate copies of rows. Recall that I used an auxiliary table of numbers (Nums) as follows to generate the requested number of copies of each row:

Relational databases contain relations . Table 11-1 is an example of a typical Employees relation, which is physically represented in the database as a table .

The preceding technique generates in the result set as many copies of each row in T1 as num_of_copies. As a practical example, suppose you need to ll an Orders table with sample data for testing. You have a Customers table with sample customer information and an Employees table with sample employee information. You want to generate, for each combination of a customer and an employee, an order for each day in January 2009. I will demonstrate this technique in the InsideTSQL2008 database. The Customers table contains 91 rows, the Employees table contains 9 rows, and for each customer-employee combination, you need an order for each day in January 2009 that is, for 31 days. The result set should contain 25,389 rows (91 9 31 = 25,389). Naturally, you want to store the result set in a target table and generate an order ID for each order.

haven't guessed yet, it's the ON clause order. Specifying the ON clause ON O.CustomerID = C.CustomerID last causes the other joins to be logically processed first; the left outer join occurs logically between Customers and the inner join of the rest of the tables. You could write the query without parentheses, and it would mean the same thing: SELECT DISTINCT C.CompanyName AS customer, S.CompanyName AS supplier FROM dbo.Customers AS C LEFT OUTER JOIN dbo.Orders AS O JOIN dbo.[Order Details] AS OD ON OD.OrderID = O.OrderID JOIN dbo.Products AS P ON P.ProductID = OD.ProductID JOIN dbo.Suppliers AS S ON S.SupplierID = P.SupplierID ON O.CustomerID = C.CustomerID;

You already have tables with customers and employees, but a table is missing you need a table to represent the days. You probably guessed already that the Nums table will assume the role of the missing table:

TABLe 11-1

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