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Requests for ancestors of a given node are also commonfor example, returning the chain of management for a given employee. Not surprisingly, the algorithms for returning ancestors using iterative logic are similar to those for returning subordinates. Simply, instead of traversing the graph starting with a given node and proceeding "downwards" to child nodes, you start with a given node and proceed "upwards" to parent nodes. Run the code in Listing 9-11 to create the fn_managers function. The function accepts an input employee ID (@empid) and, optionally, a level limit (@maxlevels), and it returns managers up to the requested number of levels away from the input employee (if a limit was specified).

IF OBJECT_ID('dbo.MyOrderValues', 'U') IS NOT NULL DROP TABLE dbo.MyOrderValues;

The attempt fails with the following error:

Inner joins are used to match rows between two tables based on some criterion. Out of the rst three logical query processing phases, inner joins apply the rst two namely, Cartesian product and ON lter. Neither phase adds outer rows. Consequently, if an INNER JOIN query contains both an ON clause and a WHERE clause, logically they are applied one after the other. With one exception, there s no difference between specifying a logical expression in the ON clause or in the WHERE clause of an INNER JOIN because no intermediate step adds outer rows between the two.

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---------------------------------------------------------------------- Function: fn_managers, Ancestors with optional level limit --- Input : @empid INT : Employee id -@maxlevels : Max number of levels to return --- Output : @Mgrs Table: id and level of managers of -input employee in all levels <= @maxlevels --- Process : * In a loop, while current manager is not null -and previous level is smaller than @maxlevels -insert into @Mgrs current manager, -and get next level manager --------------------------------------------------------------------USE tempdb; GO IF OBJECT_ID('dbo.fn_managers') IS NOT NULL DROP FUNCTION dbo.fn_managers; GO CREATE FUNCTION dbo.fn_managers (@empid AS INT, @maxlevels AS INT = NULL) RETURNS @Mgrs TABLE ( empid INT NOT NULL PRIMARY KEY, lvl INT NOT NULL ) AS BEGIN IF NOT EXISTS(SELECT * FROM dbo.Employees WHERE empid = @empid) RETURN; DECLARE @lvl AS INT; SET @lvl = 0; -- Initialize level counter with 0 -- If input @maxlevels is NULL, set it to maximum integer -- to virtually have no limit on levels SET @maxlevels = COALESCE(@maxlevels, 2147483647); WHILE @empid IS NOT NULL -- while current employee has a manager AND @lvl <= @maxlevels -- and previous level < @maxlevels BEGIN -- Insert current manager to @Mgrs

Msg 2729, Level 16, State 1, Line 1 Column 'col1' in table 'dbo.T1' cannot be used in an index or statistics or as a partition key because it is non-deterministic. Msg 1750, Level 16, State 0, Line 1 Could not create constraint. See previous errors.

The one exception is when you specify GROUP BY ALL. Remember that GROUP BY ALL adds back groups that were ltered out by the WHERE clause, but it does not add back groups that were ltered out by the ON clause. Remember also that this is a nonstandard legacy feature that you should avoid using. For performance, when not using the GROUP BY ALL option, you typically get the same plan regardless of where you place the lter expression. That s because the optimizer is aware that there s no difference. I m always cautious when saying such things related to optimization choices because the process is so dynamic. For the two supported join syntaxes, using the ANSI SQL-92 syntax, you have more exibility in choosing which clause you will use to specify a lter expression. Because logically it makes no difference where you place your lters, and typically there s also no performance difference, your guideline should be natural and intuitive writing. Write in a way that feels more natural to you and to the programmers who need to maintain your code. For example, to me a lter that matches attributes between the tables should appear in the ON clause, while a lter on an attribute from only one table should appear in the WHERE clause. I ll use the following query to return orders placed by U.S. customers:

SELECT C.custid, companyname, orderid FROM Sales.Customers AS C JOIN Sales.Orders AS O ON C.custid = O.custid WHERE country = N'USA';

The error occurs because the function doesn t meet one of the requirements for indexing, which says that the function must be schema bound . As you can see, the error message itself is not too helpful in indicating the cause of the error or in suggesting how to fix it . You need to realize that to fix the problem, you should alter the function by adding the SCHEMABINDING option:

INSERT INTO @Mgrs(empid, lvl) VALUES(@empid, @lvl); SET @lvl = @lvl + 1; -- Increment level counter -- Get next level manager SET @empid = (SELECT mgrid FROM dbo.Employees WHERE empid = @empid); END RETURN; END GO

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